本文实例为大家分享了C语言实现扫雷游戏的简易版,供大家参考,具体内容如下
game.h
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#pragma once #include <stdio.h> #include <string.h> #include <time.h> #include <windows.h> #define ROW 12 #define COL 12 #define NUMS 20 #pragma warning(disable:4996) void Menu(); void Game(); |
game.c
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#include "game.h" void Menu() { printf ( "###########################\n" ); printf ( "## 1.Play 2. Exit ##\n" ); printf ( "###########################\n" ); printf ( "请输入# " ); } void SetMines( char board[][COL], int row, int col) { int num = NUMS; while (num) { int x = rand () % 10 + 1; int y = rand () % 10 + 1; if (board[x][y] == '0' ) { board[x][y] = '1' ; num--; } } } int GetNums( char board[][COL], int row, int col, int x, int y) { return board[x - 1][y - 1] + board[x - 1][y] + \ board[x - 1][y + 1] + board[x][y + 1] + \ board[x + 1][y + 1] + board[x + 1][y] + \ board[x + 1][y - 1] + board[x][y - 1] - 8 * '0' ; } void ShowBoard( char board[][COL], int row, int col) { printf ( " " ); for ( int i = 1; i < col - 1; i++) { printf ( " %2d " , i); } printf ( "\n" ); printf ( "-------------------------------------------\n" ); for ( int i = 1; i < row - 1; i++) { printf ( "%2d|" , i); for ( int j = 1; j < col - 1; j++) { printf ( " %c |" , board[i][j]); } printf ( "\n" ); printf ( "-------------------------------------------\n" ); } } void Game() { system ( "cls" ); srand ((unsigned long ) time (NULL)); char show_board[ROW][COL]; char mine_board[ROW][COL]; memset (show_board, '*' , sizeof (show_board)); memset (mine_board, '0' , sizeof (mine_board)); SetMines(mine_board, ROW, COL); int count = (ROW - 2) * (COL - 2) - NUMS; int x = 0; int y = 0; do { ShowBoard(show_board, ROW, COL); printf ( "请输入坐标# " ); scanf ( "%d %d" , &x, &y); if (x < 1 || x > ROW - 2 || y < 1 || y > COL - 2) { printf ( "输入位置越界,请重新输入!\n" ); continue ; } if (show_board[x][y] != '*' ) { printf ( "该位置已经被排除!\n" ); continue ; } if (mine_board[x][y] == '1' ) { break ; } int num = GetNums(mine_board, ROW, COL, x, y); show_board[x][y] = num + '0' ; count--; system ( "cls" ); } while (count > 0); if (count > 0) { printf ( "你被炸死了!\n" ); ShowBoard(mine_board, ROW, COL); } else { printf ( "恭喜,你通过游戏!\n" ); } } |
main.c
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#include "game.h" void Menu() { printf ( "###########################\n" ); printf ( "## 1.Play 2. Exit ##\n" ); printf ( "###########################\n" ); printf ( "请输入# " ); } void SetMines( char board[][COL], int row, int col) { int num = NUMS; while (num) { int x = rand () % 10 + 1; int y = rand () % 10 + 1; if (board[x][y] == '0' ) { board[x][y] = '1' ; num--; } } } int GetNums( char board[][COL], int row, int col, int x, int y) { return board[x - 1][y - 1] + board[x - 1][y] + \ board[x - 1][y + 1] + board[x][y + 1] + \ board[x + 1][y + 1] + board[x + 1][y] + \ board[x + 1][y - 1] + board[x][y - 1] - 8 * '0' ; } void ShowBoard( char board[][COL], int row, int col) { printf ( " " ); for ( int i = 1; i < col - 1; i++) { printf ( " %2d " , i); } printf ( "\n" ); printf ( "-------------------------------------------\n" ); for ( int i = 1; i < row - 1; i++) { printf ( "%2d|" , i); for ( int j = 1; j < col - 1; j++) { printf ( " %c |" , board[i][j]); } printf ( "\n" ); printf ( "-------------------------------------------\n" ); } } void Game() { system ( "cls" ); srand ((unsigned long ) time (NULL)); char show_board[ROW][COL]; char mine_board[ROW][COL]; memset (show_board, '*' , sizeof (show_board)); memset (mine_board, '0' , sizeof (mine_board)); SetMines(mine_board, ROW, COL); int count = (ROW - 2) * (COL - 2) - NUMS; int x = 0; int y = 0; do { ShowBoard(show_board, ROW, COL); printf ( "请输入坐标# " ); scanf ( "%d %d" , &x, &y); if (x < 1 || x > ROW - 2 || y < 1 || y > COL - 2) { printf ( "输入位置越界,请重新输入!\n" ); continue ; } if (show_board[x][y] != '*' ) { printf ( "该位置已经被排除!\n" ); continue ; } if (mine_board[x][y] == '1' ) { break ; } int num = GetNums(mine_board, ROW, COL, x, y); show_board[x][y] = num + '0' ; count--; system ( "cls" ); } while (count > 0); if (count > 0) { printf ( "你被炸死了!\n" ); ShowBoard(mine_board, ROW, COL); } else { printf ( "恭喜,你通过游戏!\n" ); } } |
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持服务器之家。
原文链接:https://blog.csdn.net/qq_46148205/article/details/110237237