Java中对list map根据map某个key值进行排序的方法

2021-05-13 11:21做个好人XL Java教程

今天小编就为大家分享一篇Java中对list map根据map某个key值进行排序的方法，具有很好的参考价值，希望对大家有所帮助。一起跟随小编过来看看吧

实例如下所示：

				?

									package test;

									import java.util.arraylist;

									import java.util.collections;

									import java.util.comparator;

									import java.util.hashmap;

									import java.util.list;

									import java.util.map;

									public class java_listmapsort {

									  public static void main(string[] args) {

									    // todo auto-generated method stub 

									    list<map<string, object>> list = new arraylist<map<string, object>>();

									    map<string, object> map1 = new hashmap<string, object>();

									    map1.put("name", "p");

									    map1.put("cj", "5");

									    map<string, object> map2 = new hashmap<string, object>();

									    map2.put("name", "h");

									    map2.put("cj", "12");

									    map<string, object> map3 = new hashmap<string, object>();

									    map3.put("name", "f");

									    map3.put("cj", "31");

									    list.add(map1);

									    list.add(map3);

									    list.add(map2);

									    //排序前 

									    for (map<string, object> map : list) {

									      system.out.println(map.get("cj"));

									    }

									    collections.sort(list, new comparator<map<string, object>>() {

									      public int compare(map<string, object> o1, map<string, object> o2) {

									        integer name1 = integer.valueof(o1.get("cj").tostring()) ;//name1是从你list里面拿出来的一个 

									        integer name2 = integer.valueof(o2.get("cj").tostring()) ; //name1是从你list里面拿出来的第二个name

									        return name1.compareto(name2);

									      }

									    });

									    //排序后 

									    system.out.println("-------------------");

									    for (map<string, object> map : list) {

									      system.out.println(map.get("cj"));

									    }

									  }

									}