本文实例为大家分享了Java实现Floyd算法求最短路径的具体代码,供大家参考,具体内容如下
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import java.io.FileInputStream; import java.io.FileNotFoundException; import java.util.Scanner; public class TestMainIO { /** * @param args * @throws FileNotFoundException */ public static void main(String[] args) throws FileNotFoundException { TestMainIO test_print = new TestMainIO(); int [][] G = test_print.intputGragh( "D:\\Users\\test.txt" , 6 ); int [][] Dis = test_print.floyd(G, 6 ); test_print.printG(Dis, 6 ); } public void printG( int [][] G, int n){ for ( int i= 0 ;i<n;i++){ for ( int j= 0 ;j<n;j++){ System.out.println(i+ "->" +j+ " " +G[i][j]); } } } public int [][] intputGragh(String path , int num) throws FileNotFoundException{ int [][] G = new int [num][num]; for ( int i= 0 ;i<num;i++){ for ( int j= 0 ;j<num;j++){ G[i][j]= 999 ; } } Scanner in = new Scanner( new FileInputStream(path)); while (in.hasNext()) { int i = in.nextInt(); int j = in.nextInt(); int weight = in.nextInt(); G[i][j] = weight; } return G; } public int [][] floyd( int [][] G, int n){ int [][] Dis= new int [n][n]; for ( int q= 0 ;q<n;q++){ for ( int w= 0 ;w<n;w++){ Dis[q][w]=G[q][w]; } } for ( int k = 0 ; k < n; k++){ for ( int i= 0 ; i < n; i++ ){ for ( int j= 0 ; j < n; j++){ if (Dis[i][j]>Dis[i][k]+Dis[k][j]){ Dis[i][j]=Dis[i][k]+Dis[k][j]; } } } } return Dis; } } |
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持服务器之家。
原文链接:http://blog.csdn.net/limao314/article/details/14451193