本文实例讲述了java基于递归算法实现汉诺塔问题。分享给大家供大家参考,具体如下:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
|
package test; import java.util.List; import java.util.ArrayList; import java.util.Scanner; import sun.net.www.content.audio.x_aiff; /** * @author 年浩 * */ public class test { public static void move( char x, char y) { System.out.printf( "%c->%c" , x,y); System.out.println(); } public static void hanoit( int n, char one, char two, char three) { if (n== 1 ) move(one, three); else { hanoit(n- 1 , one, three, two); move(one, three); hanoit(n- 1 , two, one, three); } } public static void main(String[] args) { // TODO Auto-generated method stub Scanner cin = new Scanner(System.in); System.out.println( "请输入汉诺塔的个数" ); int a = cin.nextInt(); hanoit(a, 'x' , 'y' , 'z' ); } } |
希望本文所述对大家java程序设计有所帮助。