第一种是list中的对象实现Comparable接口,如下:
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/** * 根据order对User排序 */ public class User implements Comparable <user> { private String name; private Integer order; public String getName() { return name; } public void setName(String name) { this .name = name; } public Integer getOrder() { return order; } public void setOrder(Integer order) { this .order = order; } public int compareTo(User arg0) { return this .getOrder().compareTo(arg0.getOrder()); } } </user> |
测试一下:
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public class Test{ public static void main(String[] args) { User user1 = new User(); user1.setName( "a" ); user1.setOrder( 1 ); User user2 = new User(); user2.setName( "b" ); user2.setOrder( 2 ); List <user> list = new ArrayList <user> (); //此处add user2再add user1 list.add(user2); list.add(user1); Collections.sort(list); for (User u : list){ System.out.println(u.getName()); } } } </user> </user> |
输出结果如下
a
b
第二种方法是根据Collections.sort重载方法来实现,例如:
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/** * 根据order对User排序 */ public class User { //此处无需实现Comparable接口 private String name; private Integer order; public String getName() { return name; } public void setName(String name) { this .name = name; } public Integer getOrder() { return order; } public void setOrder(Integer order) { this .order = order; } } |
主类中这样写即可:
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public class Test{ public static void main(String[] args) { User user1 = new User(); user1.setName( "a" ); user1.setOrder( 1 ); User user2 = new User(); user2.setName( "b" ); user2.setOrder( 2 ); List <user> list = new ArrayList <user> (); list.add(user2); list.add(user1); Collections.sort(list, new Comparator <user> (){ public int compare(User arg0, User arg1) { return arg0.getOrder().compareTo(arg1.getOrder()); } }); for (User u : list){ System.out.println(u.getName()); } } } </user> </user> </user> |
输出结果如下
a
b
前者代码结构简单,但是只能根据固定的属性排序,后者灵活,可以临时指定排序项,但是代码不够简洁
多字段的场合:
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Collections.sort(list, new Comparator <user> (){ public int compare(User arg0, User arg1) { // 第一次比较专业 int i = arg0.getOrder().compareTo(arg1.getOrder()); // 如果专业相同则进行第二次比较 if (i== 0 ){ // 第二次比较 int j=arg0.getXXX().compareTo(arg1.getXXX()); // 如果学制相同则返回按年龄排序 if (j== 0 ){ return arg0.getCCC().compareTo(arg1.getCCC()); } return j; } return i; } }); </user> |
以上内容就是小编给大家介绍有关用Java集合中的Collections.sort方法如何对list排序(两种方法),希望对大家有所帮助。