在程序中要做一个复制文件夹的功能，用递归写起来很方便。后来要某位仁兄（自己知道就行了 - -）实现一个类似的，貌似不是那么顺利，这里把复制文件夹的递归代码丢出来：
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Public Shared Sub CopyDirectory(source As String, destination As String) If Directory.Exists(destination) = False Then Try Directory.CreateDirectory(destination) Catch ex As Exception Logger.LogError(Logger.SourceType.Application, "Copy build process: Cannot create folder: " & destination) Return End Try End If For Each paths As String In Directory.GetDirectories(source) CopyDirectory(paths, Path.Combine(destination, paths.Substring(paths.LastIndexOfAny({""c, "/"c}) + 1))) Next For Each files As String In Directory.GetFiles(source) Try File.Copy(files, Path.Combine(destination, files.Substring(files.LastIndexOfAny({""c, "/"c}) + 1)), True) _copiedFiles += 1 Catch ex As Exception Logger.LogError(Logger.SourceType.Application, "Copy build process: Cannot copy file: " & files) End Try Next End Sub |
递归的程序实在是很简洁很漂亮吧？后来又写了一个在文件夹中搜索文件的方法，也是递归的，那么在这里就一并丢出来：
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''' <summary>''' Search the specified file in the folder and its sub folders and return its full path name. Empty string if not found.''' </summary>''' <param name="fileName">The file to search (no folder).</param>''' <remarks></remarks>Public Shared Function SearchFile(folder As String, fileName As String) As String If Directory.Exists(folder) = False Then Return String.Empty fileName = fileName.Trim.ToLower If fileName.IndexOfAny({""c, "/"c}) >= 0 Then fileName = GetFileName(fileName) End If Dim list() As String = Directory.GetFiles(folder) For i As Integer = 0 To list.GetUpperBound(0) If GetFileName(list(i)).Trim.ToLower = fileName Then Return list(i) Next Dim directories() As String = Directory.GetDirectories(folder) For i As Integer = 0 To directories.GetUpperBound(0) Dim return_file As String = SearchFile(directories(i), fileName) If return_file.Length > 0 Then Return return_file Next Return String.EmptyEnd Function |
GetFileName是我自己写的一个把路径去掉只剩下文件名和扩展名的方法。
这两段代码实在是太简单了，所以我觉得没有什么地方要解释了（其实是准备下班走人了）。
