问题提出:
自己在做一个小网站充当练手,但是前端图片经过base64加密后传往后端在解码。但是一直都有问题,请大神赐教
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public static String base64ToImg(String src) throws IOException { String uuid = UUID.randomUUID().toString(); StringBuilder newPath = new StringBuilder(IMG_ROOT_PATH); newPath.append(separator). append(uuid). append(IMG_SUFFIX); if (src == null ){ return null ; } byte [] data = null ; Base64.Decoder decoder = Base64.getDecoder(); try (OutputStream out = new FileOutputStream(newPath.toString())) { data = decoder.decode(src); out.write(data); return newPath.toString(); } catch (IOException e) { throw new IOException(); } } |
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java.lang.IllegalArgumentException: Input byte array has wrong 4 - byte ending unit |
以上是相关的异常信息。我试图将前端的base64码粘贴到记事本然后自己在试着解码,也是同样问题。
解决办法:
IllegalArgumentException:非法参数异常,
试下这个,应该可以。
给你讲述下过程:
去了stackoverflow,debug。最后发现data为null,,加油吧,我们需要学的还很多
下次遇到问题debug下,看是哪条代码出现问题了,通过回答你,我也学到了很多
关键点在这里: throw new IOException();
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try (OutputStream out = new FileOutputStream(newPath.toString())) { out.write(data); } catch (IOException e) { e.printStackTrace(); throw new RuntimeException( "异常是这么抛出的" ); //throw new RuntimeException(e); } |
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public static String base64ToImg(String src) throws IOException { String uuid = UUID.randomUUID().toString(); StringBuilder newPath = new StringBuilder( "xx" ); newPath.append( "xx" ). append(uuid). append( "xx" ); if (src == null ) { return null ; } byte [] data = Base64.getDecoder().decode(src); try (OutputStream out = new FileOutputStream(newPath.toString())) { out.write(data); } catch (IOException e) { e.printStackTrace(); } return newPath.toString(); } |
补充另外一种常用关闭资源:
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public static String base64ToImg(String src) throws IOException { String uuid = UUID.randomUUID().toString(); StringBuilder newPath = new StringBuilder( "xx" ); newPath.append( "xx" ). append(uuid). append( "xx" ); if (src == null ) { return null ; } byte [] data = null ; OutputStream out = null ; Base64.Decoder decoder = Base64.getDecoder(); try { out = new FileOutputStream(newPath.toString()); data = decoder.decode(src); out.write(data); } catch (IOException e) { e.printStackTrace(); } finally { if (out != null ) { out.close(); } } return newPath.toString(); } |