python3 flask实现文件上传功能_Python

python3 flask实现文件上传功能

2021-03-28 00:16diyiday Python

这篇文章主要为大家详细介绍了python3 flask实现文件上传功能，文中示例代码介绍的非常详细，具有一定的参考价值，感兴趣的小伙伴们可以参考一下

本文实例为大家分享了python3-flask 文件上传操作的具体代码，供大家参考，具体内容如下

									# -*- coding: utf-8 -*-

									import os

									import uuid

									import platform

									from flask import Flask,request,redirect,url_for

									from werkzeug.utils import secure_filename

									if platform.system() == "Windows":

									 slash = '\\'

									else:

									 platform.system()=="Linux"

									 slash = '/'

									UPLOAD_FOLDER = 'upload'

									ALLOW_EXTENSIONS = set(['html', 'htm', 'doc', 'docx', 'mht', 'pdf'])

									app = Flask(__name__)

									app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER

									#判断文件夹是否存在，如果不存在则创建

									if not os.path.exists(UPLOAD_FOLDER):

									 os.makedirs(UPLOAD_FOLDER)

									else:

									 pass

									# 判断文件后缀是否在列表中

									def allowed_file(filename):

									 return '.' in filename and \

									   filename.rsplit('.', 1)[1] in ALLOW_EXTENSIONS

									@app.route('/',methods=['GET','POST'])

									def upload_file():

									 if request.method =='POST':

									  #获取post过来的文件名称，从name=file参数中获取

									  file = request.files['file']

									  if file and allowed_file(file.filename):

									   # secure_filename方法会去掉文件名中的中文

									   filename = secure_filename(file.filename)

									   #因为上次的文件可能有重名，因此使用uuid保存文件

									   file_name = str(uuid.uuid4()) + '.' + filename.rsplit('.', 1)[1]

									   file.save(os.path.join(app.config['UPLOAD_FOLDER'],file_name))

									   base_path = os.getcwd()

									   file_path = base_path + slash + app.config['UPLOAD_FOLDER'] + slash + file_name

									   print(file_path)

									   return redirect(url_for('upload_file',filename = file_name))

									 return '''

									 <!doctype html>

									 <title>Upload new File</title>

									 <h1>Upload new File</h1>

									 <form action="" method=post enctype=multipart/form-data>

									  <p><input type=file name=file>

									   <input type=submit value=Upload>

									 </form>

									 '''

									if __name__ == "__main__":

									 app.run(host='0.0.0.0',port=5000)