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Java语言实现最大堆代码示例

2021-02-27 14:17GoldArowana JAVA教程

这篇文章主要介绍了Java语言实现最大堆代码示例,具有一定参考价值,需要的朋友可以了解下。

最大堆

最大堆的特点是父元素比子元素大,并且是一棵完全二叉树。

data[1]开始存,data[0]空着不用。也可以把data[0]当成size来用。

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public class MaxHeap<T extends Comparable<? super T>> {
    private T[] data;
    private int size;
    private int capacity;
    public MaxHeap(int capacity) {
        this.data = (T[]) new Comparable[capacity + 1];
        size = 0;
        this.capacity = capacity;
    }
    public int size() {
        return this.size;
    }
    public Boolean isEmpty() {
        return size == 0;
    }
    public int getCapacity() {
        return this.capacity;
    }
    /**
   * @return 查看最大根(只看不删, 与popMax对比)
   */
    public T seekMax() {
        return data[1];
    }
    public void swap(int i, int j) {
        if (i != j) {
            T temp = data[i];
            data[i] = data[j];
            data[j] = temp;
        }
    }
    public void insert(T item) {
        size++;
        data[size] = item;
        shiftUp(size);
    }
    /**
   * @return 弹出最大根(弹出意味着删除, 与seekMax对比)
   */
    public T popMax() {
        swap(1, size--);
        shiftDown(1);
        return data[size + 1];
    }
    /**
   * @param child 孩子节点下角标是child,父节点下角表是child/2
   */
    public void shiftUp(int child) {
        while (child > 1 && data[child].compareTo(data[child / 2]) > 0) {
            swap(child, child / 2);
            child = child / 2;
        }
    }
    /**
   * @param a data数组中某个元素的下角标
   * @param b data数组中某个元素的下角标
   * @return 哪个元素大就返回哪个的下角标
   */
    private int max(int a, int b) {
        if (data[a].compareTo(data[b]) < 0) {
            //如果data[b]大
            return b;
            //返回b
        } else {
            //如果data[a]大
            return a;
            //返回a
        }
    }
    /**
   * @param a data数组中某个元素的下角标
   * @param b data数组中某个元素的下角标
   * @param c data数组中某个元素的下角标
   * @return 哪个元素大就返回哪个的下角标
   */
    private int max(int a, int b, int c) {
        int biggest = max(a, b);
        biggest = max(biggest, c);
        return biggest;
    }
    /**
   * @param father 父节点下角标是father,左右两个孩子节点的下角表分别是:father*2 和 father*2+1
   */
    public void shiftDown(int father) {
        while (true) {
            int lchild = father * 2;
            //左孩子
            int rchild = father * 2 + 1;
            //右孩子
            int newFather = father;
            //newFather即将更新,父、左、右三个结点谁大,newFather就是谁的下角标
            if (lchild > size) {
                //如果该father结点既没有左孩子,也没有右孩子
                return;
            } else if (rchild > size) {
                //如果该father结点只有左孩子,没有右孩子
                newFather = max(father, lchild);
            } else {
                //如果该father结点既有左孩子,又有右孩子
                newFather = max(father, lchild, rchild);
            }
            if (newFather == father) {
                //说明father比两个子结点都要大,表名已经是大根堆,不用继续调整了
                return;
            } else {
                //否则,还需要继续调整堆,直到满足大根堆条件为止
                swap(father, newFather);
                //值进行交换
                father = newFather;
                //更新father的值,相当于继续调整shiftDown(newFather)
            }
        }
    }
    public static void main(String[] args) {
        //创建大根堆
        MaxHeap<Integer> maxHeap = new MaxHeap<Integer>(100);
        //向堆里存
        for (int i = 0; i < 100; i++) {
            maxHeap.insert((int) (Math.random() * 100));
        }
        //创建数组
        Integer[] arr = new Integer[100];
        //从堆里取,放进数组里
        for (int i = 0; i < 100; i++) {
            arr[i] = maxHeap.popMax();
            System.out.print(arr[i] + " ");
        }
        System.out.println();
    }
}

最大堆:shiftDown()函数与上面不一样

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public class MaxHeap<T extends Comparable<? super T>> {
    private T[] data;
    private int size;
    private int capacity;
    public MaxHeap(int capacity) {
        data = (T[]) new Comparable[capacity + 1];
        this.capacity = capacity;
        size = 0;
    }
    public int size() {
        return size;
    }
    public Boolean isEmpty() {
        return size == 0;
    }
    public void insert(T item) {
        data[size + 1] = item;
        size++;
        shiftUp(size);
    }
    /**
   * @return 弹出最大根(弹出意味着删除, 与seekMax对比)
   */
    public T popMax() {
        T ret = data[1];
        swap(1, size);
        size--;
        shiftDown(1);
        return ret;
    }
    /**
   * @return 查看最大根(只看不删, 与popMax对比)
   */
    public T seekMax() {
        return data[1];
    }
    public void swap(int i, int j) {
        if (i != j) {
            T temp = data[i];
            data[i] = data[j];
            data[j] = temp;
        }
    }
    public void shiftUp(int k) {
        while (k > 1 && data[k / 2].compareTo(data[k]) < 0) {
            swap(k, k / 2);
            k /= 2;
        }
    }
    public void shiftDown(int father) {
        while (2 * father <= size) {
            int newFather = 2 * father;
            if (newFather + 1 <= size && data[newFather + 1].compareTo(data[newFather]) > 0) {
                //data[j] data[j+1]两者取大的那个
                newFather = newFather + 1;
            }
            if (data[father].compareTo(data[newFather]) >= 0) {
                break;
            } else {
                swap(father, newFather);
                //值进行交换
                father = newFather;
                //newFather是(2*father)或者是(2*father+1),也就是继续shiftDown(newFather);
            }
        }
    }
    public static void main(String[] args) {
        //创建大根堆
        MaxHeap<Integer> maxHeap = new MaxHeap<Integer>(100);
        //向堆里存
        for (int i = 0; i < 100; i++) {
            maxHeap.insert((int) (Math.random() * 100));
        }
        //创建数组
        Integer[] arr = new Integer[100];
        //从堆里取,放进数组里
        for (int i = 0; i < 100; i++) {
            arr[i] = maxHeap.popMax();
            System.out.print(arr[i] + " ");
        }
        System.out.println();
    }
}

总结

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原文链接:http://www.cnblogs.com/noKing/p/7954898.html

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