本文实例讲述了python检查字符串是否是正确ISBN的方法。分享给大家供大家参考。具体实现方法如下：
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
|
def isISBN(isbn): """Checks if the passed string is a valid ISBN number.""" if len(isbn) != 10 or not isbn[:9].isdigit(): return False if not (isbn[9].isdigit() or isbn[9].lower() == "x"): return False tot = sum((10 - i) * int(c) for i, c in enumerate(isbn[:-1])) checksum = (11 - tot % 11) % 11 if isbn[9] == 'X' or isbn[9] == 'x': return checksum == 10 else: return checksum == int(isbn[9]) ok = """031234161X 0525949488 076360013X 0671027360 0803612079 0307263118 0684856093 0767916565 0071392319 1400032806 0765305240"""for code in ok.split(): assert isISBN(code) bad = """0312341613 052594948X 0763600138 0671027364 080361207X 0307263110 0684856092 0767916567 0071392318 1400032801 0765305241 031234161 076530Y241 068485609Y"""for code in bad.split(): assert not isISBN(code) print "Tests of isISBN()passed." |
希望本文所述对大家的Python程序设计有所帮助。
