在开发应用程序的过程中，如果有多个应用，通常会通过一个portal 门户来集成，这个portal 是所有应用程序的入口，用户一旦在portal 登录之后，进入另外一个系统，就需要类似的单点登录(SSO). 进入各个子系统的时候，就不需要再次登录, 当然类似的功能，你可以通过专业的单点登录软件来实现，也可以自己写数据库token 等方式来实现。其实还有一个比较简单的方法，就是通过 portal 封装已经登录过的用户的消息，写到http header 之中，然后把请求forward 到各个子系统中去，而各子系统从 http header 中获取用户名，作为是否登录过的校验或者合法的校验。
总结了几种处理http Header 的方法：
利用 HttpServletRequest
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import javax.servlet.http.HttpServletRequest; //... private HttpServletRequest request; //get request headers private Map<String, String> getHeadersInfo() { Map<String, String> map = new HashMap<String, String>(); Enumeration headerNames = request.getHeaderNames(); while (headerNames.hasMoreElements()) { String key = (String) headerNames.nextElement(); String value = request.getHeader(key); map.put(key, value); } return map; } |
一个典型的例子如下：
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"headers" : { "Host" : "yihaomen.com", "Accept-Encoding" : "gzip,deflate", "X-Forwarded-For" : "66.249.x.x", "X-Forwarded-Proto" : "http", "User-Agent" : "Mozilla/5.0 (compatible; Googlebot/2.1; +http://www.google.com/bot.html)", "X-Request-Start" : "1389158003923", "Accept" : "*/*", "Connection" : "close", "X-Forwarded-Port" : "80", "From" : "googlebot(at)googlebot.com"} |
获取 user-agent
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import javax.servlet.http.HttpServletRequest; //... private HttpServletRequest request; private String getUserAgent() { return request.getHeader("user-agent"); } |
一个典型的例子如下：
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Mozilla/5.0 (compatible; Googlebot/2.1; +http://www.google.com/bot.html) |
利用 spring mvc 获取 HttpRequest Header 的例子
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import java.util.Enumeration;import java.util.HashMap;import java.util.Map;import javax.servlet.http.HttpServletRequest;import org.springframework.beans.factory.annotation.Autowired;import org.springframework.stereotype.Controller;import org.springframework.web.bind.annotation.PathVariable;import org.springframework.web.bind.annotation.RequestMapping;import org.springframework.web.bind.annotation.RequestMethod;import org.springframework.web.servlet.ModelAndView;@Controller@RequestMapping("/site")public class SiteController { @Autowired private HttpServletRequest request; @RequestMapping(value = "/{input:.+}", method = RequestMethod.GET) public ModelAndView getDomain(@PathVariable("input") String input) { ModelAndView modelandView = new ModelAndView("result"); modelandView.addObject("user-agent", getUserAgent()); modelandView.addObject("headers", getHeadersInfo()); return modelandView; } //get user agent private String getUserAgent() { return request.getHeader("user-agent"); } //get request headers private Map<String, String> getHeadersInfo() { Map<String, String> map = new HashMap<String, String>(); Enumeration headerNames = request.getHeaderNames(); while (headerNames.hasMoreElements()) { String key = (String) headerNames.nextElement(); String value = request.getHeader(key); map.put(key, value); } return map; }} |
也许有人会说，Http Header 是可以模拟的，那么自己可以构造一个用来欺骗这些系统， 是的，的确是这样，所以在用Http Header 来传值得时候，一定要记得，所有的请求都必须经过 portal 来处理，然后 forward 到各子系统，就不会出现这个问题了。因为portal 首先拦截用户发起的所有的请求，如果是构造的用户，在portal 的sessiion 也是没有记录的，仍然会跳转到登录页面，如果在protal 的 session 中记录，而且 Http Header 中也有记录，那么在子系统就是合法的用户，然后自己可以根据一些要求处理业务逻辑了
JSP/Java获取HTTP header信息(request)例子
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<%//header.jspout.println("Protocol: " + request.getProtocol() + "<br>");out.println("Scheme: " + request.getScheme() + "<br>");out.println("Server Name: " + request.getServerName() + "<br>" );out.println("Server Port: " + request.getServerPort() + "<br>");out.println("Protocol: " + request.getProtocol() + "<br>");out.println("Server Info: " + getServletConfig().getServletContext().getServerInfo() + "<br>");out.println("Remote Addr: " + request.getRemoteAddr() + "<br>");out.println("Remote Host: " + request.getRemoteHost() + "<br>");out.println("Character Encoding: " + request.getCharacterEncoding() + "<br>");out.println("Content Length: " + request.getContentLength() + "<br>");out.println("Content Type: "+ request.getContentType() + "<br>");out.println("Auth Type: " + request.getAuthType() + "<br>");out.println("HTTP Method: " + request.getMethod() + "<br>");out.println("Path Info: " + request.getPathInfo() + "<br>");out.println("Path Trans: " + request.getPathTranslated() + "<br>");out.println("Query String: " + request.getQueryString() + "<br>");out.println("Remote User: " + request.getRemoteUser() + "<br>");out.println("Session Id: " + request.getRequestedSessionId() + "<br>");out.println("Request URL: " + request.getRequestURL() + "<br>");out.println("Request URI: " + request.getRequestURI() + "<br>");out.println("Servlet Path: " + request.getServletPath() + "<br>");out.println("Created : " + session.getCreationTime() + "<br>");out.println("LastAccessed : " + session.getLastAccessedTime() + "<br>");out.println("Accept: " + request.getHeader("Accept") + "<br>");out.println("Host: " + request.getHeader("Host") + "<br>");out.println("Referer : " + request.getHeader("Referer") + "<br>");out.println("Accept-Language : " + request.getHeader("Accept-Language") + "<br>");out.println("Accept-Encoding : " + request.getHeader("Accept-Encoding") + "<br>");out.println("User-Agent : " + request.getHeader("User-Agent") + "<br>");out.println("Connection : " + request.getHeader("Connection") + "<br>");out.println("Cookie : " + request.getHeader("Cookie") + "<br>");%> |
关于request.getHeader("Referer")的说明
request.getHeader("Referer")获取来访者地址。只有通过链接访问当前页的时候，才能获取上一页的地址；否则request.getHeader("Referer")的值为Null，通过window.open打开当前页或者直接输入地址，也为Null。
以上就是小编为大家带来的java 获取HttpRequest Header的几种方法(必看篇)的全部内容了，希望对大家有所帮助，多多支持服务器之家~
