Python 解码Base64 得到码流格式文本实例_Python

Python 解码Base64 得到码流格式文本实例

2020-05-01 10:30见习老中医 Python

今天小编就为大家分享一篇Python 解码Base64 得到码流格式文本实例，具有很好的参考价值，希望对大家有所帮助。一起跟随小编过来看看吧

我就废话不多说了，直接上代码吧！

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									# coding:utf8

									import base64

									def BaseToFlow():

									  while True:

									    str = input("Please input src: ")

									    flag = input("Please input Decode - 1 or Encode - 2: ")

									    if str == "":

									      str = "ApIAGBcEAAAEBO6x3nLykEEhjWMX1wHs"

									    if flag == "":

									      flag = "1"

									    if flag == "1":

									      print("Decoding ...")

									      dst = base64.b64decode(str)

									      # print(type(dst))

									      # <class 'bytes'>

									      # print(dst)

									      # b'\x02\x92\x00\x18\x17\x04\x00\x00\x04\x04\xee\xb1\xder\xf2\x90A!\x8dc\x17\xd7\x01\xec'

									      # print(dst.hex()) --去掉\0x前缀 得到一个字符串

									      # 02920018170400000404eeb1de72f29041218d6317d701ec

									      HexFormat(dst.hex())

									    elif flag == "2":

									      print("Encoding ...")

									      dst = base64.b64encode(str)

									      print(dst)

									def HexFormat(str):

									  """

									  :param str: 16进制连续字符串

									  :return: 码流格式的16进制串

									  """

									  i = 1

									  str2 = ""

									  while (i <= len(str)):

									    str2 = str2 + str[i - 1] + str[i] + " "

									    if (i + 1) %16 == 0 and (i + 1) % 32 != 0:

									      str2 = str2 + " "

									    elif (i + 1) %32 == 0:

									      str2 = str2 + "\n"

									    i = i + 2

									if __name__ == '__main__':

									  BaseToFlow()

结果：

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									Please input src: 

									Please input Decode - 1 or Encode - 2: 

									Decoding ...

									02 92 00 18 17 04 00 00 04 04 ee b1 de 72 f2 90

									41 21 8d 63 17 d7 01 ec