本文实例讲述了TP5框架简单登录功能实现方法。分享给大家供大家参考，具体如下：
登录方法,验证
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public function login(){ if(request()->isGet()){ return view('login'); }elseif(request()->isPost()){ $model = new InfoModel(); $name = input('name'); //获取表单提交的姓名 $pwd = input('password');//获取表单提交的密码 if($model->LoginVerify($name,$pwd)){ $verify = input('code'); //获取验证码的值 $cap = new Captcha(); //实例化验证码类 if($cap->check($verify)){ $this->success('登录成功','admin/ShowIndex');//登录成功跳转首页 /*echo '登录成功';*/ }else{ $this->error('验证码错误','admin/admin/login'); } } }} |
表单
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<div class="form-group"> <div class="field field-icon-right"> <input type="password" class="input input-big" name="password" placeholder="登录密码" data-validate="required:请填写密码" /> <span class="icon icon-key margin-small"></span> </div> </div> <div class="form-group"> <div class="field"> <input type="text" class="input input-big" name="code" placeholder="填写右侧的验证码" data-validate="required:请填写右侧的验证码" /> <img src="{:captcha_src()}" alt="" width="150" height="32" class="passcode" style="height:43px;cursor:pointer;" οnclick="this.src=this.src+'?'"> </div></div> |
model类,要与表名同名
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<?phpnamespace app\admin\model;use think\Model;class Info extends Model{#登录验证 public function LoginVerify($name,$pwd) { //$re = $this->where(["username =>'$name',pwd=>'$pwd'"])->find(); $re = $this->where("username='$name' and pwd='$pwd'")->find(); if($re){ return $re; }else{ return null; } }} |
希望本文所述对大家基于ThinkPHP框架的PHP程序设计有所帮助。
原文链接：https://blog.csdn.net/lingluo110700/article/details/82353876
