本文实例为大家分享了C++实现俄罗斯方块的具体代码，供大家参考，具体内容如下
工具：vc++2010,图库:EasyX
先看效果图片
纯手写，没有面向对象思想,看全部源码
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#include <stdio.h>#include <graphics.h>#include <time.h>#include <conio.h>#define BLOCK_COUNT 5#define BLOCK_WIDTH 5#define BLOCK_HEIGHT 5#define UNIT_SIZE 20#define START_X 130#define START_Y 30#define KEY_UP 72#define KEY_RIGHT 77#define KEY_LEFT 75#define KEY_SPACE 32#define KEY_DOWN 76typedef enum{ BLOCK_UP, BLOCK_RIGHT, BLOCK_DOWN, BLOCK_LEFT}block_dir_t;typedef enum{ MOVE_DOWN, MOVE_LEFT, MOVE_RIGHT}move_dir_t;int speed = 500;int NextIndex = -1;//下一个方块种类int BlockIndex = -1;//当前方块种类int score = 0;//分数int rank = 0;//等级int visit[30][15];//访问数组int markcolor[30][15];//表示颜色int minX = 30;int minY = 30;int color[BLOCK_COUNT]={ GREEN,CYAN,MAGENTA,BROWN,YELLOW};int block[BLOCK_COUNT*4][BLOCK_HEIGHT][BLOCK_WIDTH] = { //条形方块 { 0,0,0,0,0, 0,0,1,0,0, 0,0,1,0,0, 0,0,1,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,0,0, 0,1,1,1,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,1,0,0, 0,0,1,0,0, 0,0,1,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,0,0, 0,1,1,1,0, 0,0,0,0,0, 0,0,0,0,0}, //L形方块 { 0,0,0,0,0, 0,0,1,0,0, 0,0,1,0,0, 0,0,1,1,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,0,0, 0,1,1,1,0, 0,1,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,1,1,0,0, 0,0,1,0,0, 0,0,1,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,1,0, 0,1,1,1,0, 0,0,0,0,0, 0,0,0,0,0}, //田字型 { 0,0,0,0,0, 0,1,1,0,0, 0,1,1,0,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,1,1,0,0, 0,1,1,0,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,1,1,0,0, 0,1,1,0,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,1,1,0,0, 0,1,1,0,0, 0,0,0,0,0, 0,0,0,0,0}, //T字形方块 { 0,0,0,0,0, 0,1,1,1,0, 0,0,1,0,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,1,0, 0,0,1,1,0, 0,0,0,1,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,1,0,0, 0,1,1,1,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,1,0,0, 0,0,1,1,0, 0,0,1,0,0, 0,0,0,0,0}, //Z字形方块 { 0,0,0,0,0, 0,1,1,0,0, 0,0,1,1,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,1,0, 0,0,1,1,0, 0,0,1,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,1,1,0,0, 0,0,1,1,0, 0,0,0,0,0, 0,0,0,0,0}, { 0,0,0,0,0, 0,0,0,1,0, 0,0,1,1,0, 0,0,1,0,0, 0,0,0,0,0}};//欢迎界面void welcome(){ //初始化画布 initgraph(550,660); //设置窗口标题 HWND window = GetHWnd();//获取窗口 SetWindowText(window,_T("俄罗斯方块 GWF"));//设置窗口标题 //设置文本字体样式 setfont(0,30,_T("微软雅黑")); setcolor(YELLOW); outtextxy(150,200,_T("俄罗斯方块")); setfont(0,10,_T("微软雅黑")); outtextxy(175,300,_T("IT编程从俄罗斯方块开始")); Sleep(3000); }//初始化游戏屏幕void initGameScene(){ char str[16]; //清除屏幕 cleardevice(); rectangle(27,27,336,635); rectangle(29,29,334,633); rectangle(370,50,515,195); setfont(24,0,_T("楷体")); setcolor(LIGHTGRAY); outtextxy(405,215,_T("下一个")); setcolor(RED); outtextxy(405,280,_T("分数")); sprintf(str,"%d",score); outtextxy(415,310,str); outtextxy(405,375,_T("等级")); sprintf(str,"%d",rank); outtextxy(415,405,str); setcolor(LIGHTBLUE); outtextxy(390,475,"操作说明"); outtextxy(390,500,"↑:旋转"); outtextxy(390,525,"↓:下降"); outtextxy(390,550,"→:向右"); outtextxy(390,575,"←:向左"); outtextxy(390,600,"空格:暂停");}void drawBlock(int x,int y){//右上角画出方块 setcolor(color[NextIndex]); setfont(23,0,"楷体"); for(int i= 0;i<BLOCK_HEIGHT;i++){ for(int j= 0;j<BLOCK_WIDTH;j++){ if(block[NextIndex*4][i][j] == 1){ outtextxy(x+UNIT_SIZE*j,y+UNIT_SIZE*i,"■"); } } }}void drawBlock(int x,int y,int blockIndex,block_dir_t dir){//按索引画出什么方块指定位置方块指定方向 setcolor(color[blockIndex]); setfont(23,0,"楷体"); int id = blockIndex*4+dir; for(int i= 0;i<BLOCK_HEIGHT;i++){ for(int j= 0;j<BLOCK_WIDTH;j++){ if(block[id][i][j] == 1){ outtextxy(x+UNIT_SIZE*j,y+UNIT_SIZE*i,"■"); } } }}void clearBlock(int x, int y){ setcolor(BLACK); setfont(23,0,"楷体"); for(int i= 0;i<BLOCK_HEIGHT;i++){ for(int j= 0;j<BLOCK_WIDTH;j++){ outtextxy(x+UNIT_SIZE*j,y+UNIT_SIZE*i,"■"); } }}void clearBlock(int x, int y,block_dir_t dir){ setcolor(BLACK); int id = BlockIndex *4+dir; y+=START_Y; for(int i= 0;i<BLOCK_HEIGHT;i++){ for(int j= 0;j<BLOCK_WIDTH;j++){ if(block[id][i][j] == 1){ outtextxy(x+UNIT_SIZE*j,y+UNIT_SIZE*i,"■"); } } }}void nextblock(){ clearBlock(391,71);//清除右上角方块 //随机选择一种方块 srand(time(NULL));//时间函数的返回值产生随机数种子 NextIndex = rand()%BLOCK_COUNT; drawBlock(391,71);//画出方块}//如果在指定位置可以向方向移动int moveable(int x0,int y0,move_dir_t moveDir,block_dir_t blockDir){ int x = (y0 - minY)/UNIT_SIZE; int y = (x0 - minX)/UNIT_SIZE; int id = BlockIndex * 4+blockDir; int ret = 1; if(moveDir == MOVE_DOWN){ for(int i = 0;i<5;i++){ for(int j = 0;j<5;j++){ if(block[id][i][j] == 1 &&(x+i+1>=30 || visit[x+i+1][y+j]==1)){ ret=0; } } } }else if(moveDir == MOVE_LEFT){ for(int i = 0;i<5;i++){ for(int j = 0;j<5;j++){ if(block[id][i][j] == 1 &&(y+j==0 || visit[x+i][y+j-1]==1)){ ret=0; } } } }else if(moveDir == MOVE_RIGHT){ for(int i = 0;i<5;i++){ for(int j = 0;j<5;j++){ if(block[id][i][j] == 1 &&(y+j+1>=15 || visit[x+i][y+j+1]==1)){ ret=0; } } } } return ret;}void failCheck(){//游戏是否结束 if(!moveable(START_X,START_Y,MOVE_DOWN,BLOCK_UP)){ setcolor(WHITE); setfont(45,0,"隶体"); outtextxy(75,300,"GAME OVER!"); Sleep(1000); system("pause"); closegraph(); exit(0); }}int wait(int interval){//等待 int count = interval/5; for(int i = 0;i<count;i++){ Sleep(5); if(kbhit()){ return 0; } }}//判断当前方向是否可以转到指定方向int rotatable(int x,int y,block_dir_t dir){ int id= BlockIndex * 4 +dir; int xIndex = (y-minY)/20; int yIndex = (x-minX)/20; if(!moveable(x,y,MOVE_DOWN,dir)){ return 0 ; } for(int i = 0;i<5;i++){ for(int j = 0;j<5;j++){ if(block[id][i][j] ==1&&(yIndex+j<0||yIndex+j>=15||visit[xIndex+i][yIndex+j] ==1)){ return 0 ; } } } return 1;}void mark(int x,int y,int blockIndex,block_dir_t dir){ int id = blockIndex*4+dir; int x2 = (y-minY)/20; int y2 = (x-minX)/20; for(int i=0;i<5;i++){ for(int j=0;j<5;j++){ if(block[id][i][j] ==1){ visit[x2+i][y2+j]=1; markcolor[x2+i][y2+j]=color[blockIndex]; } } }}void clear_down(int x){//消除第x行,并把上面的行都下移 for(int i = x;i>0;i--){ for(int j=0;j<15;j++){ if(visit[i-1][j]){//上面有东西 visit[i][j]=1; markcolor[i][j]=markcolor[i-1][j]; setcolor(markcolor[i][j]); outtextxy(20*j+minX,20*i+minY,"■"); }else{ visit[i][j] =0; setcolor(BLACK); outtextxy(20*j+minX,20*i+minY,"■"); } } } //清除最顶层那一行,就是行标位0的哪一行 setcolor(BLACK); for(int j = 0;j<15;j++){ visit[0][j] = 0; outtextxy(20*j+minX,minY,"■"); }}void updataGrade(){//更新等级提示//假设:50分一级 char str[10]; rank = score/50; sprintf(str,"%d",rank); outtextxy(425,405,str); //更新速度,等级越高速度越快,speed越小 //最慢是500,最快是50 speed = 500-rank*50; if(speed<=0){ speed = 50; }}void addScore(int lines){//更新分数,line表示消除的行数 char str[32]; setcolor(RED); score+=lines*10; sprintf(str,"%d",score); outtextxy(415,310,str);}void check(){//消去方块 int i,j; int clearLines =0; for(i=29;i>=0;i--){ for(j=0;j<15 && visit[i][j];j++); //执行到此处有两种情况, //1.第I行没有满,即表示有空位,此时j<15 //2.第i行已经满了,j就大于等于15 if(j>=15){ //此时第i行已经满了,就需要消除第i行 clear_down(i);//清除第i行,并把上面的行都下移动 i++; clearLines++; } } //更新分数 addScore(clearLines); //更新等级 updataGrade();}void move(){ int x = START_X; int y = START_Y; int k = 0; int curSpeed = speed; block_dir_t blockDir = BLOCK_UP; //检查游戏是否结束 failCheck(); while(1){ if(kbhit()){ int key = getch(); if(KEY_SPACE == key){ getch(); } } //清除当前方块 clearBlock(x,k,blockDir); if(kbhit()){ int key = getch(); if(KEY_UP == key){//变形 block_dir_t nextDir = (block_dir_t)((blockDir+1)%4); if(rotatable(x,y+k,nextDir)){ blockDir= nextDir; } }else if(KEY_DOWN == key){//乡下加速 curSpeed = 50; }else if(KEY_RIGHT == key){//右移动 if(moveable(x,y+k+20,MOVE_RIGHT,blockDir)){ x+=20; } }else if(KEY_LEFT == key){//左移动 if(moveable(x,y+k+20,MOVE_LEFT,blockDir)){ x-=20; } } } k+=20; //绘制当前方块 drawBlock(x,y+k,BlockIndex,blockDir); wait(curSpeed); //方块降落到底层的固化处理 if(!moveable(x,y+k,MOVE_DOWN,blockDir)){ mark(x,y+k,BlockIndex,blockDir); break; } }}void newblock(){ //确定即将使用的方块 BlockIndex = NextIndex; //绘制方块从顶部掉下来 drawBlock(START_X,START_Y); //新出现的方块等一下 Sleep(100); //右上角绘制下一个方块 nextblock(); //向下降落的动作 move();}int main (void){ welcome(); initGameScene(); //产生新方块 nextblock(); Sleep(500); memset(visit,0,sizeof(visit)); while(1){ newblock(); //消除满行,并更新分数和速度 check(); } system("pause"); closegraph(); return 0;} |
分析项目：
1.必须要有欢迎界面
2.搭建合理的边界,就是游戏范围
3.逻辑1:先出现右上方的方块样式,等待一段时间,将右上方的样式在游戏区打印出
4.逻辑2,方块降落,要擦除原先印记,将1改为0
5.逻辑3,热键控制移动方向,暂停及变形,且不能移动出界,判断方块是否还能移动
6.逻辑4,方块凝固在下方不出界
7.逻辑5,最下面一行方块叠满了,消去它并把上面的行都下移(分两种情况),并且再次检查这一行
8.逻辑6,计算消除行数次数,统计分数,控制休眠时间长度
9.逻辑7,每次移动先判断是否能移动,默认结束程序,在合理游戏区返回false,结束界面
总结：从界面开始到完整的架构,功能后实现,一步一步,逻辑严谨,思路清晰,注释在代码里。
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持服务器之家。
原文链接：https://blog.csdn.net/acararduino/article/details/103947960
