今天在下脚本的时候遇到一个问题,比如有这样的一个字符串 t = "book123456",想把尾部的数字全部去掉,只留下“book”,自己用正则试了下,是实现了,但速度不是很快,于是问了一下同事,他给的解决的方法确实很简洁,也让自己长了知识点,如下:
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import string t.rstrip(string.digits) |
这样就全部将数字移除了,顺便将string这个模块看了下文档,也有一定的收获。
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>>> import string >>> string.digits '0123456789' >>> string.hexdigits '0123456789abcdefABCDEF' >>> string.octdigits '01234567' >>> string.letters 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ' >>> string.lowercase 'abcdefghijklmnopqrstuvwxyz' >>> string.uppercase 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' >>> string.printable '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~ \t\n\r\x0b\x0c' >>> string.punctuation '!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~' >>> string.whitespace '\t\n\x0b\x0c\r ' >>> |
同时string可以将字符串和int,float相互转化:
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>>> string.atof( "1.23" ) 1.23 >>> string.atof( "1" ) 1.0 |
转换的时候还可以制定进制的转化
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>>> string.atoi( "20" ) 20 >>> string.atoi( "20" ,base = 10 ) 20 >>> string.atoi( "20" ,base = 16 ) 32 >>> string.atoi( "20" ,base = 8 ) 16 >>> string.atoi( "20" ,base = 2 ) Traceback (most recent call last): File "", line 1 , in <module> File "/usr/lib64/python2.6/string.py" , line 403 , in atoi return _int(s, base) ValueError: invalid literal for int () with base 2 : '20' >>> string.atoi( "101" ,base = 2 ) 5 >>> string.atoi( "101" ,base = 6 ) 37 |
capwords(s, sep = None)以sep作为分隔符,分割字符串是s,然后将每个字符串的首字母大写
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>>> string.capwords( "this is a dog" ) 'This Is A Dog' >>> string.capwords( "this is a dog" ,sep = " " ) 'This Is A Dog' >>> string.capwords( "this is a dog" ,sep = "s" ) 'This is a dog' >>> string.capwords( "this is a dog" ,sep = "o" ) 'This is a doG' >>> |
maketrans(s, r)创建一个s到r的转换列表,然后可以使用translate()方法来实现
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>>> replist = string.maketrans( "123" , "abc" ) >>> replist1 = string.maketrans( "456" , "xyz" ) >>> s = "123456789" >>> s.translate(replist) 'abc456789' >>> s.translate(replist1) '123xyz789' |
以上这篇python 移除字符串尾部的数字方法就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持服务器之家。
原文链接:https://blog.csdn.net/lulongfei172006/article/details/51744505