脚本之家,脚本语言编程技术及教程分享平台!
分类导航

Python|VBS|Ruby|Lua|perl|VBA|Golang|PowerShell|Erlang|autoit|Dos|bat|

服务器之家 - 脚本之家 - Python - Python单链表简单实现代码

Python单链表简单实现代码

2020-08-21 10:18阳光_如此耀眼 Python

这篇文章主要介绍了Python单链表简单实现代码,结合实例形式分析了Python单链表的具体定义与功能实现技巧,需要的朋友可以参考下

本文实例讲述了Python单链表简单实现代码。分享给大家供大家参考,具体如下:

用Python模拟一下单链表,比较简单,初学者可以参考参考

?
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
#coding:utf-8
class Node(object):
  def __init__(self, data):
    self.data = data
    self.next = None
class NodeList(object):
  def __init__(self, node):
    self.head = node
    self.head.next = None
    self.end = self.head
  def add_node(self, node):
    self.end.next = node
    self.end = self.end.next
  def length(self):
    node = self.head
    count = 1
    while node.next is not None:
      count += 1
      node = node.next
    return count
  # delete node and return it's value
  def delete_node(self, index):
    if index+1 > self.length():
      raise IndexError('index out of bounds')
    i = 0
    node = self.head
    while True:
      if i==index-1:
        break
      node = node.next
      i += 1
    tmp_node = node.next
    node.next = node.next.next
    return tmp_node.data
  def show(self):
    node = self.head
    node_str = ''
    while node is not None:
      if node.next is not None:
        node_str += str(node.data) + '->'
      else:
        node_str += str(node.data)
      node = node.next
    print node_str
  # Modify the original position value and return the old value
  def change(self, index, data):
    if index+1 > self.length():
      raise IndexError('index out of bounds')
    i = 0
    node = self.head
    while True:
      if i == index:
        break
      node = node.next
      i += 1
    tmp_data = node.data
    node.data = data
    return tmp_data
  # To find the location of index value
  def find(self, index):
    if index+1 > self.length():
      raise IndexError('index out of bounds')
    i = 0
    node = self.head
    while True:
      if i == index:
        break
      node = node.next
      i += 1
    return node.data
#test case
n1 = Node(0)
n2 = Node(1)
n3 = Node(2)
n4 = Node(3)
n5 = Node(4)
node_list = NodeList(n1)
node_list.add_node(n2)
node_list.add_node(n3)
node_list.add_node(n4)
node_list.add_node(n5)
#node = node_list.delete_node(3)
#print node
#d = node_list.change(0,88)
data = node_list.find(5)
print data
node_list.show()
 

希望本文所述对大家Python程序设计有所帮助。

延伸 · 阅读

精彩推荐