本文实例讲述了python定时执行指定函数的方法。分享给大家供大家参考。具体实现方法如下：
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# time a function using time.time() and the a @ function decorator# tested with Python24 vegaseat 21aug2005import timedef print_timing(func): def wrapper(*arg): t1 = time.time() res = func(*arg) t2 = time.time() print '%s took %0.3f ms' % (func.func_name, (t2-t1)*1000.0) return res return wrapper# declare the @ decorator just before the function, invokes print_timing()@print_timingdef getPrimeList(n): """ returns a list of prime numbers from 2 to < n using a sieve algorithm""" if n < 2: return [] if n == 2: return [2] # do only odd numbers starting at 3 s = range(3, n+1, 2) # n**0.5 may be slightly faster than math.sqrt(n) mroot = n ** 0.5 half = len(s) i = 0 m = 3 while m <= mroot: if s[i]: j = (m*m-3)//2 s[j] = 0 while j < half: s[j] = 0 j += m i = i+1 m = 2*i+3 return [2]+[x for x in s if x]if __name__ == "__main__": print "prime numbers from 2 to <10,000,000 using a sieve algorithm" primeList = getPrimeList(10000000) time.sleep(2.5)"""my output -->prime numbers from 2 to <10,000,000 using a sieve algorithmgetPrimeList took 4750.000 ms""" |
希望本文所述对大家的Python程序设计有所帮助。
