由于最近项目,有这样一个需求,是把数据库中的两列数据互换,经过好久才搞定,这里写个简单实例,做过记录。
1.创建表及记录用于测试
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CREATE TABLE `product` ( `id` int (10) unsigned NOT NULL AUTO_INCREMENT COMMENT '产品id' , ` name ` varchar (50) NOT NULL COMMENT '产品名称' , `original_price` decimal (5,2) unsigned NOT NULL COMMENT '原价' , `price` decimal (5,2) unsigned NOT NULL COMMENT '现价' , PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8; INSERT INTO `product` (`id`, ` name `, `original_price`, `price`) VALUES ( NULL , '雪糕' , '5' , '3.5' ), ( NULL , '鲜花' , '18' , '15' ), ( NULL , '甜点' , '25' , '12.5' ), ( NULL , '玩具' , '55' , '45' ), ( NULL , '钱包' , '285' , '195' ); |
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mysql> select * from product; + ----+--------+----------------+--------+ | id | name | original_price | price | + ----+--------+----------------+--------+ | 1 | 雪糕 | 5.00 | 3.50 | | 2 | 鲜花 | 18.00 | 15.00 | | 3 | 甜点 | 25.00 | 12.50 | | 4 | 玩具 | 55.00 | 45.00 | | 5 | 钱包 | 285.00 | 195.00 | + ----+--------+----------------+--------+ 5 rows in set (0.00 sec) |
2.互换original_price与price的值
新手可能会使用以下方法进行互换
update product set original_price=price,price=original_price;
但这样执行的结果只会使original_price与price的值都是price的值,因为update有顺序的,
先执行original_price=price , original_price的值已经更新为price,
然后执行price=original_price,这里相当于没有更新。
执行结果:
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mysql> select * from product; + ----+--------+----------------+--------+ | id | name | original_price | price | + ----+--------+----------------+--------+ | 1 | 雪糕 | 5.00 | 3.50 | | 2 | 鲜花 | 18.00 | 15.00 | | 3 | 甜点 | 25.00 | 12.50 | | 4 | 玩具 | 55.00 | 45.00 | | 5 | 钱包 | 285.00 | 195.00 | + ----+--------+----------------+--------+ 5 rows in set (0.00 sec) mysql> update product set original_price=price,price=original_price; Query OK, 5 rows affected (0.00 sec) Rows matched: 5 Changed: 5 Warnings: 0 mysql> select * from product; + ----+--------+----------------+--------+ | id | name | original_price | price | + ----+--------+----------------+--------+ | 1 | 雪糕 | 3.50 | 3.50 | | 2 | 鲜花 | 15.00 | 15.00 | | 3 | 甜点 | 12.50 | 12.50 | | 4 | 玩具 | 45.00 | 45.00 | | 5 | 钱包 | 195.00 | 195.00 | + ----+--------+----------------+--------+ 5 rows in set (0.00 sec) |
正确的互换方法如下:
update product as a, product as b set a.original_price=b.price, a.price=b.original_price where a.id=b.id;
执行结果:
mysql> select * from product;
+----+--------+----------------+--------+
| id | name | original_price | price |
+----+--------+----------------+--------+
| 1 | 雪糕 | 5.00 | 3.50 |
| 2 | 鲜花 | 18.00 | 15.00 |
| 3 | 甜点 | 25.00 | 12.50 |
| 4 | 玩具 | 55.00 | 45.00 |
| 5 | 钱包 | 285.00 | 195.00 |
+----+--------+----------------+--------+
5 rows in set (0.00 sec)
mysql> update product as a, product as b set a.original_price=b.price, a.price=b.original_price where a.id=b.id;
Query OK, 5 rows affected (0.01 sec)
Rows matched: 5 Changed: 5 Warnings: 0
mysql> select * from product;
+----+--------+----------------+--------+
| id | name | original_price | price |
+----+--------+----------------+--------+
| 1 | 雪糕 | 3.50 | 5.00 |
| 2 | 鲜花 | 15.00 | 18.00 |
| 3 | 甜点 | 12.50 | 25.00 |
| 4 | 玩具 | 45.00 | 55.00 |
| 5 | 钱包 | 195.00 | 285.00 |
+----+--------+----------------+--------+
5 rows in set (0.00 sec)
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