本文实例讲述了Python通过递归遍历出集合中所有元素的方法。分享给大家供大家参考。具体实现方法如下：
复制代码代码如下:
'''''通过递归遍历出集合中的所有元素
Created on 2013-9-29
@author: L.Eric
'''
def print_List(list_nums):
for each_item in list_nums :
if isinstance(each_item,list):
print_List(each_item)
else:
print(each_item)
movies = ["aaa","bbb","ccc","ddd",["qqq","sss",["mmm","rrr",["tt","ccs"]]]]
print_List(movies)
Created on 2013-9-29
@author: L.Eric
'''
def print_List(list_nums):
for each_item in list_nums :
if isinstance(each_item,list):
print_List(each_item)
else:
print(each_item)
movies = ["aaa","bbb","ccc","ddd",["qqq","sss",["mmm","rrr",["tt","ccs"]]]]
print_List(movies)
希望本文所述对大家的Python程序设计有所帮助。
