Django提供了翻页器。用Django的Paginator类实现
一、views模块导入Paginator类实现数据分页
ApiTest/apiviews.py
每行都加了注释，希望有助于理解。
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
|
from django.shortcuts import renderfrom ApiTest.models import ApiTestfrom django.contrib.auth.decorators import login_requiredfrom django.core.paginator import Paginator, EmptyPage, PageNotAnInteger, InvalidPage@login_requireddef api_test_manage(request): username = request.session.get('user', '') # 获取所有接口测试数据 apitest_list = ApiTest.objects.all().order_by('id') # 生成Paginator对象对数据分页，每页显示10条数据 paginator = Paginator(apitest_list,10) # 使用request.GET.get()函数获取url中的page参数的数值。默认第1页 page = request.GET.get('page', 1) # 把获取的当前页码数转换成整数类型 current_page = int(page) try: # 获取查询页数的接口数据列表，page()函数会判断page实参是否是有效数字。page()函数源码附在文章的最后 apitest_list = paginator.page(page) except PageNotAnInteger: apitest_list = paginator.page(1) except (EmptyPage, InvalidPage): # paginator.num_pages apitest_list = paginator.page(paginator.num_pages) return render(request, "apitest_manage.html", {'user': username, 'apitests': apitest_list}) |
二、将views的数据渲染到前端模板上
在对应的html文件中加入此段代码即可。
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
|
<div class="container"> <ul class="pagination" id="pager"> {# 上一页链接 #} {% if apitests.has_previous %} <li class="previous"><a href="/apitest_manage/?page={{ apitests.previous_page_number }}" rel="external nofollow" >上一页</a></li> {% else %} <li class="previous disabled"><a href="#" rel="external nofollow" rel="external nofollow" >上一页</a></li> {% endif %} {# 中间数字显示 #} {% for num in apitests.paginator.page_range %} {% if num == currentPage %} <li class="item active"><a href="/apitest_manage/?page={{ num }}" rel="external nofollow" rel="external nofollow" >{{ num }}</a></li> {% else %} <li class="item"><a href="/apitest_manage/?page={{ num }}" rel="external nofollow" rel="external nofollow" >{{ num }}</a></li> {% endif %} {% endfor %} {# 下一页链接 #} {% if apitests.has_next %} {# 如果有下一页，则正常显示下一页链接 #} <li class="next"><a href="/apitest_manage/?page={{ apitests.next_page_number }}" rel="external nofollow" >下一页</a></li> {% else %} <li class="next disabled"><a href="#" rel="external nofollow" rel="external nofollow" >下一页</a></li> {% endif %} </ul></div> |
三、效果展示
四、Paginator类源码
此类主要用在views文件
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
|
class Paginator: def __init__(self, object_list, per_page, orphans=0, allow_empty_first_page=True): self.object_list = object_list self._check_object_list_is_ordered() self.per_page = int(per_page) self.orphans = int(orphans) self.allow_empty_first_page = allow_empty_first_page def validate_number(self, number): """Validate the given 1-based page number.""" try: if isinstance(number, float) and not number.is_integer(): raise ValueError number = int(number) except (TypeError, ValueError): raise PageNotAnInteger(_('That page number is not an integer')) if number < 1: raise EmptyPage(_('That page number is less than 1')) if number > self.num_pages: if number == 1 and self.allow_empty_first_page: pass else: raise EmptyPage(_('That page contains no results')) return number def get_page(self, number): """ Return a valid page, even if the page argument isn't a number or isn't in range. """ try: number = self.validate_number(number) except PageNotAnInteger: number = 1 except EmptyPage: number = self.num_pages return self.page(number) def page(self, number): """Return a Page object for the given 1-based page number.""" number = self.validate_number(number) bottom = (number - 1) * self.per_page top = bottom + self.per_page if top + self.orphans >= self.count: top = self.count return self._get_page(self.object_list[bottom:top], number, self) def _get_page(self, *args, **kwargs): """ Return an instance of a single page. This hook can be used by subclasses to use an alternative to the standard :cls:`Page` object. """ return Page(*args, **kwargs) @cached_property def count(self): """Return the total number of objects, across all pages.""" c = getattr(self.object_list, 'count', None) if callable(c) and not inspect.isbuiltin(c) and method_has_no_args(c): return c() return len(self.object_list) @cached_property def num_pages(self): """Return the total number of pages.""" if self.count == 0 and not self.allow_empty_first_page: return 0 hits = max(1, self.count - self.orphans) return ceil(hits / self.per_page) @property def page_range(self): """ Return a 1-based range of pages for iterating through within a template for loop. """ return range(1, self.num_pages + 1) def _check_object_list_is_ordered(self): """ Warn if self.object_list is unordered (typically a QuerySet). """ ordered = getattr(self.object_list, 'ordered', None) if ordered is not None and not ordered: obj_list_repr = ( '{} {}'.format(self.object_list.model, self.object_list.__class__.__name__) if hasattr(self.object_list, 'model') else '{!r}'.format(self.object_list) ) warnings.warn( 'Pagination may yield inconsistent results with an unordered ' 'object_list: {}.'.format(obj_list_repr), UnorderedObjectListWarning, stacklevel=3 ) |
五、Page类源码
此类主要用在html文件
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
|
class Page(collections.abc.Sequence): def __init__(self, object_list, number, paginator): self.object_list = object_list self.number = number self.paginator = paginator def __repr__(self): return '<Page %s of %s>' % (self.number, self.paginator.num_pages) def __len__(self): return len(self.object_list) def __getitem__(self, index): if not isinstance(index, (int, slice)): raise TypeError( 'Page indices must be integers or slices, not %s.' % type(index).__name__ ) # The object_list is converted to a list so that if it was a QuerySet # it won't be a database hit per __getitem__. if not isinstance(self.object_list, list): self.object_list = list(self.object_list) return self.object_list[index] def has_next(self): return self.number < self.paginator.num_pages def has_previous(self): return self.number > 1 def has_other_pages(self): return self.has_previous() or self.has_next() def next_page_number(self): return self.paginator.validate_number(self.number + 1) def previous_page_number(self): return self.paginator.validate_number(self.number - 1) def start_index(self): """ Return the 1-based index of the first object on this page, relative to total objects in the paginator. """ # Special case, return zero if no items. if self.paginator.count == 0: return 0 return (self.paginator.per_page * (self.number - 1)) + 1 def end_index(self): """ Return the 1-based index of the last object on this page, relative to total objects found (hits). """ # Special case for the last page because there can be orphans. if self.number == self.paginator.num_pages: return self.paginator.count return self.number * self.paginator.per_page |
到此这篇关于Django实现翻页的示例代码的文章就介绍到这了,更多相关Django 翻页内容请搜索服务器之家以前的文章或继续浏览下面的相关文章希望大家以后多多支持服务器之家！
原文链接：https://blog.csdn.net/weixin_38851970/article/details/107554847
