本文实例为大家分享了C++实现会员管理程序的具体代码，供大家参考，具体内容如下
设计快捷店会员的简单管理程序。基本要求如下：
（1）定义人民币RMB类，实现人民币的基本运算和显示。
（2）定义会员member类，表示会员的基本信息，包括：编号（按建立会员的顺序自动生成），姓名，密码，电话。提供输入、输出信息等功能。
（3）由RMB类和member类共同派生一个会员卡memberCar类，提供新建会员、充值、消费和查询余额等功能。
（4）main函数定义一个memberCar类数组或链表，保存会员卡，模拟一个快捷店的会员卡管理功能，主要包括：
① 新建会员；
② 已有会员充值；
③ 已有会员消费（凭密码，不能透支）；
④ 输出快捷店当前会员数，营业额（收、支情况）。
代码：
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#include<iostream>#include<String.h>using namespace std;class RMB{ int yuan,jiao,fen;public: RMB(int y=0,int j=0,int f=0){ yuan=y; jiao=j; fen=f; } RMB(double x) { int n = int((x + 0.005) * 100); yuan = n / 100; jiao = (n - yuan * 100) / 10; fen = n % 10; } operator double() { return (yuan + jiao * 0.1 + fen * 0.01); } ~RMB() {} friend ostream & operator<<(ostream&output, const RMB&m){ output << m.yuan << "元" << m.jiao << "角" << m.fen << "分" << endl; return output; } friend istream & operator>>(istream&input, RMB&m){ cout << "元："; input >> m.yuan; cout << "角："; input >> m.jiao; cout << "分："; input >> m.fen; return input; }};class member{public: static int number; char name[20],code[10], phoneNumber[12]; static int bianhao() { number++; return number; } member(char*a,char*c,char*p){ strcpy(name,a); strcpy(code,c); strcpy(phoneNumber,p); } ~member() {} friend istream&operator>>(istream&input, member&A) { cout << "please input name: " << endl; input >> A.name; cout << "please input code: " << endl; input >> A.code; cout << "please input phone number : " << endl; input >> A.phoneNumber; return input; } friend ostream&operator<<(ostream&output, member&A) { output << "the information of member:" << endl; output << "number" << '\t' << "name" << '\t' << "phone" << endl; output << A.bianhao() << '\t' << A.name << '\t' << A.phoneNumber << endl; return output; }};int member::number=0;class memberCar:public RMB,public member{public: RMB income, outcome, balance; memberCar*next; memberCar(char*a, char*c, char*p):member(a,c,p){ balance = 0; income = 0; outcome = 0; } ~memberCar() {} friend ostream&operator<<(ostream&output, const memberCar&A){ output << "the information of member:" << endl; output << "number" << '\t' << "name" << '\t' << "phone" << '\t' << '\t' << "balance" << endl; output << A.bianhao() << '\t' << A.name << '\t' << A.phoneNumber << '\t' << A.balance << endl; return output;}void recharge() { cout << "How much do you want to recharge?" << '\n' << "please input the money : " << endl; cin >> income; balance =balance + income; cout << "your balance : " << balance << endl; }void cost() { char y[10]; cout << "please input your code : " << endl; cin >> y; if (strncmp(code, y, 10)==0) { cout << "please input the money you cost : " << endl; cin >> outcome; if (outcome > balance) { cout << "your balance is not enough ! " << endl; } else { balance = balance - outcome; cout << "your balance : "<< balance; } } else { cout << "your code is wrong ! " << endl; } } void query(){ cout << "your balance : " << balance; }};void AddFront(memberCar*&h, memberCar*&t){ t->next = h; h = t;}void FindList(memberCar*head, int n = 2){ char s[20]; cout << "please input your name : " << endl; cin >> s; while (head) { if (strncmp(head->name, s, 20) == 0) { switch (n) { case 2: (*head).recharge(); break; case 3: (*head).cost(); break; } } head = head->next; }}void ShowList(memberCar*head){ int count = 0; RMB I=0, O=0; while (head) { count++; I=I+head->income; O = O + head->outcome; head = head->next; } cout << "the number of member : " << count << endl; cout << "the income of the store : " << I << endl; cout << "the outcome of the store : " << O << endl; cout << "turn-over of the store : " << (I - O) << endl;}int main(){ int choice; memberCar*head = NULL, *p; do { cout << "please choice:\n"; cout << "1 : new member, 2 : recharge, 3 : purchase , 4 :output the number of member and turn-over,other number is over! " << endl; cin >> choice; switch (choice) { case 1: { cout << "input information of new member : " << endl; char a[20],c[10],h[12]; cout << "please input name: " << endl; cin>>a; cout << "please input code: " << endl; cin>>c; cout << "please input phone number : " << endl; cin>>h; p = new memberCar(a, c, h); AddFront(head, p); cout << *p << endl; break; } case 2: { FindList(head, 2); break; } case 3: { FindList(head, 3); break; } case 4: { ShowList(head); break; } } } while (choice); return 0;} |
运行结果：
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原文链接：https://blog.csdn.net/qq_15719613/article/details/105738982
