游戏规则：
一付扑克牌，去掉大小王，每个玩家发3张牌，最后比大小，看谁赢。
有以下几种牌：
豹子：三张一样的牌，如3张6.
顺金：又称同花顺，即3张同样花色的顺子， 如红桃 5、6、7
顺子：又称拖拉机，花色不同，但是顺子，如红桃5、方片6、黑桃7，组成的顺子
对子：2张牌一样
单张：单张最大的是A
这几种牌的大小顺序为， 豹子>顺金>顺子>对子>单张
程序需要实现的点：
- 先生成一付完整的扑克牌
- 给5个玩家随机发牌
- 统一开牌，比大小，输出赢家是谁
主要思路：
把各种牌用积分来计算，最后加上三张牌的基础积分。即：最终积分=基础积分+牌型积分。最后比较最红积分，谁的积分大，谁排名就靠前。 附上源码：
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# -*- coding: utf-8 -*-"""# @Time : 2021-01-07 14:55# @author : jianwei# @Software : PyCharm"""import randomimport operatorpuke = [] # 存储扑克牌num_list = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']hua_list = ['梅花', '红桃', '黑桃', '方块']sotr_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4, '7': 5, '8': 6, '9': 7, '10': 8, 'J': 9, 'Q': 10, 'K': 11, 'A': 12, '对子': 15, '顺子': 30, '顺金': 60, '豹子': 100}count_new_list = [] # 存储玩家分数和排序后排名count_dic = {} # 存储玩家分数# 准备52张扑克for hua in hua_list: for num in num_list: a = hua + num puke.append(a)player_dic = {'玩家1': [], '玩家2': [], '玩家3': [], '玩家4': [], '玩家5': []}# 随机给五个玩家发牌# print(len(puke))for key, value in player_dic.items(): for i in range(3): plate = random.sample(puke, 3) player_dic[key] = plate for i in plate: puke.remove(i)# print(player_dic)# 获取玩家的牌型def paixing(list1): num = [] huase = [] for i in list1: a = i[2:] b = i[:2] num.append(a) huase.append(b) return num, huase# 对数字的牌型进行排序def sotr(num): new_num = [] sort_list2 = [] list1 = [] for i in num: new_num.append(sotr_dic[i]) new_num = sorted(new_num) for new in new_num: sort_list2.append([k for k, v in sotr_dic.items() if v == new]) for m in sort_list2: for n in m: list1.append(n) return list1# 对玩家的牌形统计分数def count(num, huase): a = 0 base_count = sotr_dic[num[0]] + sotr_dic[num[1]] + sotr_dic[num[2]] if num[0] == num[1] and num[1] == num[2]: paixing = '豹子' a = base_count + sotr_dic[paixing] # print(paixing, a) elif (sotr_dic[num[0]] + 1 == sotr_dic[num[1]] and sotr_dic[num[2]] - 1 == sotr_dic[num[1]]) and (huase[0] == huase[ 1] and huase[1] == huase[2]): paixing = '顺金' a = base_count + sotr_dic[paixing] # print(paixing, a) elif (sotr_dic[num[0]] + 1 == sotr_dic[num[1]]) and (sotr_dic[num[2]] - 1 == sotr_dic[num[1]]) and ( huase[0] != huase[ 1] or huase[1] != huase[2]): paixing = '顺子' a = base_count + sotr_dic[paixing] # print(paixing, a) elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or ( num[0] == num[2] and num[1] != num[0]): paixing = '对子' a = base_count + sotr_dic[paixing] # print(paixing, a) else: a = base_count return a# 对存储玩家分数的字典进行排序def compare(count_dic): d = list(zip(count_dic.values(), count_dic.keys())) return sorted(d, reverse=True)for key, value in player_dic.items(): # print(key,value) num, huase = paixing(value) # print(num,huase) num = sotr(num) # print(num, huase) count1 = count(num, huase) # print(count1) count_dic[key] = count1 print(key + "的牌为：" + str(value)) count_new_list = compare(count_dic)# print(count_new_list)print('最终排名：' + "\t" + count_new_list[0][1] + "第一名" + "\t" + count_new_list[1][1] + "第二名" + "\t" + count_new_list[2][ 1] + "第三名" + "\t" + count_new_list[3][1] + "第四名" + "\t" + count_new_list[4][1] + "第五名") |
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原文链接：https://blog.csdn.net/qq_48657881/article/details/112918817
