简介
pycurl类似于Python的urllib,但是pycurl是对libcurl的封装,速度更快。
本文使用的是pycurl 7.43.0.1版本。
Apache下配置Basic认证
生成basic密码文件
1
|
htpasswd -bc passwd.basic test 123456 |
开启mod_auth_basic
1
|
LoadModule auth_basic_module modules/mod_auth_basic.so |
配置到具体目录
1
2
3
4
5
6
|
< Directory "D:/test/basic"> AuthName "Basic Auth Dir" AuthType Basic AuthUserFile conf/passwd.basic require valid-user </ Directory > |
重启Apache
Apache下配置Digest认证
生成Digest密码文件
1
|
htdigest -c passwd.digest "Digest Encrypt" test |
开启mod_auth_digest
1
|
LoadModule auth_digest_module modules/mod_auth_digest.so |
配置到具体目录
1
2
3
4
5
6
7
|
< Directory "D:/test/digest"> AuthType Digest AuthName "Digest Encrypt" # 要与密码的域一致 AuthDigestProvider file AuthUserFile conf/passwd.digest require valid-user </ Directory > |
重启Apache
验证Basic认证
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
|
# -*- coding: utf-8 -*- import pycurl try : from io import BytesIO except ImportError: from StringIO import StringIO as BytesIO buffer = BytesIO() c = pycurl.Curl() c.setopt(c.URL, 'http://test/basic/' ) c.setopt(c.WRITEDATA, buffer ) c.setopt(c.HTTPAUTH, c.HTTPAUTH_BASIC) c.setopt(c.USERNAME, 'test' ) c.setopt(c.PASSWORD, '123456' ) c.perform() print ( 'Status: %d' % c.getinfo(c.RESPONSE_CODE)) print ( buffer .getvalue()) c.close() |
验证Digest认证
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
|
# -*- coding: utf-8 -*- import pycurl try : from io import BytesIO except ImportError: from StringIO import StringIO as BytesIO buffer = BytesIO() c = pycurl.Curl() c.setopt(c.URL, 'http://test/digest/' ) c.setopt(c.WRITEDATA, buffer ) c.setopt(c.HTTPAUTH, c.HTTPAUTH_DIGEST) c.setopt(c.USERNAME, 'test' ) c.setopt(c.PASSWORD, '123456' ) c.perform() print ( 'Status: %d' % c.getinfo(c.RESPONSE_CODE)) print ( buffer .getvalue()) c.close() |
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持服务器之家。
原文链接:https://blog.csdn.net/lilongsy/article/details/79086569